$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_{a}$ and $\lambda_{g}$ are the wavelengths of light in air and glass respectively,then:

Unpolarised red light is incident on the surface of a lake at an incident angle $\theta_{R}$. An observer seeing the light reflected from the water surface through a polariser notices that on rotating the polariser,the intensity of light drops to zero at a certain orientation. The red light is replaced by unpolarised blue light. The observer sees the same effect with reflected blue light at an incident angle $\theta_{B}$. Then,

The velocity of light in air is $3 \times 10^8 \, ms^{-1}$ and that in water is $2.2 \times 10^8 \, ms^{-1}$. The polarising angle of incidence is.......$^o$

$A$ ray of light is incident on the surface of a glass plate at Brewster's angle $\phi$. If $\mu$ is the refractive index of glass with respect to air,then the angle between the reflected and the refracted ray is:

Let the speed of light in a medium be $V$ and the polarising angle be $i_p$. If $C$ is the speed of light in vacuum,what is the relation between them?

For a given medium,the polarizing angle is $60^{\circ}$. The critical angle for this medium is . . . . . .