$A$ ray of light is incident at a polarising angle such that its deviation is $24^{\circ}$. Then the angle of incidence is: (in $^{\circ}$)

When an unpolarized light falls at a particular angle on a glass plate (placed in air), it is observed that the reflected beam is linearly polarized. The angle of the refracted beam with respect to the normal is . . . . . . . $(\tan ^{-1}(1.52)=57.7^{\circ}$, refractive indices of air and glass are $1.00$ and $1.52$, respectively) (in $^{\circ}$)

The critical angle of a certain medium is $\sin^{-1}\left(\frac{3}{5}\right)$. The polarizing angle of the medium is

Unpolarised light is incident on the boundary between two dielectric media,whose dielectric constants are $2.8$ (medium $1$) and $6.8$ (medium $2$),respectively. To satisfy the condition that the reflected and refracted rays are perpendicular to each other,the angle of incidence should be $\tan ^{-1}\left(1+\frac{10}{\theta}\right)^{\frac{1}{2}}$. The value of $\theta$ is $.............$ (Given for dielectric media,$\mu_{r}=1$)

The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index $n$) is

The velocity of light in air is $3 \times 10^8 \, ms^{-1}$ and that in water is $2.2 \times 10^8 \, ms^{-1}$. The polarising angle of incidence is.......$^o$