$A$ stationary wave is formed having $4$ nodes along the $120 \,cm$ length of the string. The wavelength of the wave is (in $\,cm$)

Give the values of the amplitude at a node and an anti-node in a stationary wave.

The velocity of waves in a string fixed at both ends is $2 \ m/s$. The string forms standing waves with nodes $5.0 \ cm$ apart. The frequency of vibration of the string in $Hz$ is

$A$ wave $y = a \cos (kx + \omega t)$ superimposes on another wave to form a stationary wave having a node at $x = 0$. What is the equation of the other wave?

For a stationary wave, $y = 12 \cos \left( \frac{\pi x}{10} \right) \sin(36\pi t) \text{ cm}$, the distance between a node and the successive antinode is (in $\text{ cm}$)

$A$ wave represented by the equation $y = a \cos (kx - \omega t)$ is superposed with another wave to form a stationary wave such that the point $x = 0$ is a node. The equation for the other wave is: