A transverse wave Y=2 sin (0.01 x+30 t) moves | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given wave equation is $Y=2 \sin (0.01 x+30 t)$.Comparing this with the standard wave equation $Y=A \sin (kx+\omega t)$:We get the wave number

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) The given wave equation is $Y=2 \sin (0.01 x+30 t)$.Comparing this with the standard wave equation $Y=A \sin (kx+\omega t)$:We get the wave number $k = 0.01 \ cm^{-1}$ and angular frequency $\omega = 30 \ rad/s$.The wave velocity $v$ is given by $v = \frac{\omega}{k} = \frac{30}{0.01} = 3000 \ cm/s$.Converting the velocity to meters per second: $v = 30 \ m/s$.The length of the string $L$ is the distance traveled by the wave in time $t = 0.5 \ s$.$L = v 	imes t = 30 \ m/s 	imes 0.5 \ s = 15 \ m$.

$A$ transverse wave $Y=2 \sin (0.01 x+30 t)$ moves on a stretched string from one end to another end in $0.5 \ s$. If $x$ and $y$ are in $cm$ and $t$ in $s$,then the length of the string is: (in $m$)

Similar Questions

Two sound waves having a phase difference of $60^{\circ}$ have a path difference of

The equation of a longitudinal wave is represented as $y = 20 \cos \pi (50t - x)$. Its wavelength is ..... $cm$.

The displacement of two sinusoidal waves is given by the equations:
$y_1 = 8 \sin(20x - 30t)$
$y_2 = 8 \sin(25x - 40t)$
Then the phase difference between the waves at time $t = 2 \ s$ and distance $x = 5 \ cm$ will be:

The speed of a wave in a certain medium is $960\, m/s$. If $3600$ waves pass over a certain point of the medium in $1\, minute$,the wavelength is .... $metres$.

$A$ wave equation which gives the displacement along the $Y$ direction is given by the equation $y = 10^4 \sin(60t + 2x)$,where $x$ and $y$ are in metres and $t$ is time in seconds. This represents a wave:

Vedclass Test Series

Exam Paper Generator

Online Exam Module