$A$ body moves along a circular path of radius $15 \ cm$. It starts from a point on the circular path and reaches the end of the diameter in $3 \ s$. The angular speed of the body in $rad/s$ is

Two cars of masses $m_{1}$ and $m_{2}$ are moving in circles of radii $r_{1}$ and $r_{2}$ respectively. Their angular speeds $\omega_{1}$ and $\omega_{2}$ are such that they both complete one revolution in the same time $t$. The ratio of the linear speed of $m_{1}$ to the linear speed of $m_{2}$ is:

$A$ particle moves in the $x-y$ plane according to the rules $x = a \sin \omega t$ and $y = a \cos \omega t$. The particle follows:

As shown in the figure,a particle is moving with a constant speed $v = \pi \, m/s$ in a circular path. Considering its motion from point $A$ to point $B$,where the angle subtended at the center is $120^{\circ}$,the magnitude of the average velocity is:

$A$ cyclist starts from the centre $O$ of a circular park of radius $1\, km$ and moves along the path $OPRQO$ as shown in the figure. If he maintains a constant speed of $10\, m/s$,what is his acceleration at point $R$ in magnitude and direction?

$A$ particle is moving in a horizontal circle with constant speed. It has constant