C_6H_5COCl + C_6H_5COONa xrightarrow{Delta} t | vedclass

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Question

(D) The reaction between benzoyl chloride $(C_6H_5COCl)$ and sodium benzoate $(C_6H_5COONa)$ is a nucleophilic acyl substitution reaction.In this reac

Vedclass · Accepted Answer

Benzoic anhydride

Vedclass · Answer

(D) The reaction between benzoyl chloride $(C_6H_5COCl)$ and sodium benzoate $(C_6H_5COONa)$ is a nucleophilic acyl substitution reaction.In this reaction,the carboxylate oxygen of the sodium benzoate acts as a nucleophile and attacks the carbonyl carbon of the benzoyl chloride,displacing the chloride ion.This results in the formation of benzoic anhydride $((C_6H_5CO)_2O)$ and sodium chloride $(NaCl)$ as a byproduct.The reaction is represented as: $C_6H_5COCl + C_6H_5COONa \xrightarrow{\Delta} (C_6H_5CO)_2O + NaCl$.Therefore,the correct option is $D$.

$C_6H_5COCl + C_6H_5COONa \xrightarrow{\Delta} \text{ . . . . . . }$.

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