$A$ reaction is first order with respect to a reactant $A$ and second order with respect to reactant $B$. What is the effect on the rate when the concentration of both $A$ and $B$ is doubled?

  • A
    Eight times
  • B
    Three times
  • C
    Doubled
  • D
    Sixteen times

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$t_{1/2} =$ constant confirms the first order reaction. If $a^2 t_{1/2} =$ constant,it confirms that the order of reaction is ($a =$ initial concentration of reactant).

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For the reaction $2A + B \rightarrow C + D$,select the correct rate law based on the following data:
$1$. $[A] = 0.1, [B] = 0.1, \text{Initial Rate} = 7.5 \times 10^{-3}$
$2$. $[A] = 0.3, [B] = 0.2, \text{Initial Rate} = 9.0 \times 10^{-2}$
$3$. $[A] = 0.3, [B] = 0.4, \text{Initial Rate} = 3.6 \times 10^{-1}$
$4$. $[A] = 0.4, [B] = 0.1, \text{Initial Rate} = 3.0 \times 10^{-2}$

In the reaction $2A + B \to A_2B$,if the concentration of $A$ is doubled and the concentration of $B$ is halved,then the rate of the reaction will:

The data for the reaction $A + B \to C$ is given below:
$Exp$ $[A]_0$ $[B]_0$ Initial Rate
$1$ $0.012$ $0.035$ $0.10$
$2$ $0.024$ $0.035$ $0.80$
$3$ $0.012$ $0.070$ $0.10$
$4$ $0.024$ $0.070$ $0.80$

Determine the rate law for the reaction.

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