frac{sin 3theta + sin 5theta + sin 7theta + s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given expression: $\frac{\sin 3	heta + \sin 5	heta + \sin 7	heta + \sin 9	heta}{\cos 3	heta + \cos 5	heta + \cos 7	heta + \cos 9	heta}$ Gr

Vedclass · Accepted Answer

$	an 6	heta$

Vedclass · Answer

(C) Given expression: $\frac{\sin 3	heta + \sin 5	heta + \sin 7	heta + \sin 9	heta}{\cos 3	heta + \cos 5	heta + \cos 7	heta + \cos 9	heta}$ Group the terms: $\frac{(\sin 9	heta + \sin 3	heta) + (\sin 7	heta + \sin 5	heta)}{(\cos 9	heta + \cos 3	heta) + (\cos 7	heta + \cos 5	heta)}$ Using the sum-to-product formulas $\sin A + \sin B = 2 \sin \frac{A+B}{2} \cos \frac{A-B}{2}$ and $\cos A + \cos B = 2 \cos \frac{A+B}{2} \cos \frac{A-B}{2}$: Numerator: $2 \sin 6	heta \cos 3	heta + 2 \sin 6	heta \cos 	heta = 2 \sin 6	heta (\cos 3	heta + \cos 	heta)$ Denominator: $2 \cos 6	heta \cos 3	heta + 2 \cos 6	heta \cos 	heta = 2 \cos 6	heta (\cos 3	heta + \cos 	heta)$ Dividing the numerator by the denominator: $\frac{2 \sin 6	heta (\cos 3	heta + \cos 	heta)}{2 \cos 6	heta (\cos 3	heta + \cos 	heta)} = \frac{\sin 6	heta}{\cos 6	heta} = 	an 6	heta$.

$\frac{\sin 3\theta + \sin 5\theta + \sin 7\theta + \sin 9\theta}{\cos 3\theta + \cos 5\theta + \cos 7\theta + \cos 9\theta} = $

Similar Questions

If $\sin \theta = \frac{12}{13}$ where $0 < \theta < \frac{\pi}{2}$ and $\cos \phi = -\frac{3}{5}$ where $\pi < \phi < \frac{3\pi}{2}$,then $\sin(\theta + \phi)$ is equal to:

Prove that $\frac{\sin x+\sin 3x}{\cos x+\cos 3x} = \tan 2x$.

$\frac{1}{4} [\sqrt{3} \cos 23^\circ - \sin 23^\circ] = $

If $\frac{x}{\cos \theta} = \frac{y}{\cos \left( \theta - \frac{2\pi}{3} \right)} = \frac{z}{\cos \left( \theta + \frac{2\pi}{3} \right)},$ then $x + y + z = $

$1+\cos 10^{\circ}+\cos 20^{\circ}+\cos 30^{\circ}=$

Vedclass Test Series

Exam Paper Generator

Online Exam Module