A voltmeter of very high resistance is connec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The two $8 \ \Omega$ resistors are connected in parallel to each other.Their equivalent resistance $R_{eq}$ is given by:$R_{eq} = \frac{8 	imes 8

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) The two $8 \ \Omega$ resistors are connected in parallel to each other.Their equivalent resistance $R_{eq}$ is given by:$R_{eq} = \frac{8 	imes 8}{8 + 8} = \frac{64}{16} = 4 \ \Omega$The total resistance of the circuit is:$R_{total} = 6 \ \Omega + 4 \ \Omega = 10 \ \Omega$The current $I$ flowing through the circuit is:$I = \frac{V_{source}}{R_{total}} = \frac{10 \ V}{10 \ \Omega} = 1 \ A$The voltmeter is connected across the $6 \ \Omega$ resistor. Since the voltmeter has a very high resistance,it does not draw significant current,and the voltage across the $6 \ \Omega$ resistor is:$V = I 	imes R = 1 \ A 	imes 6 \ \Omega = 6 \ V$

$A$ voltmeter of very high resistance is connected in the circuit as shown in the figure. The voltage shown by this voltmeter will be . . . . . . . (in $V$)

Similar Questions

In the given circuit,if the current flowing through the $5 \Omega$ resistor is $0.5 \text{ A}$,then the value of $E$ is: (in $\text{ V}$)

In the circuit shown,the resistance $r$ is a variable resistance. If for $r = fR$,the heat generation in $r$ is maximum,then the value of $f$ is:

What is the equivalent resistance between $A$ and $B$ in the figure below if $R = 3\,\Omega$?

$A$ cell of emf $1.8 \ V$ gives a current of $17 \ A$ when directly connected to an ammeter of resistance $0.06 \ \Omega$. The internal resistance of the cell is: (in $\Omega$)

What is the effective resistance between $A$ and $B$ for the given infinite resistor network?

Vedclass Test Series

Exam Paper Generator

Online Exam Module