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(B) The quantization of charge is given by the formula $q = ne$,where $q$ is the total charge,$n$ is the number of electrons,and $e$ is the elementary

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$2.2 	imes 10^{12}$

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(B) The quantization of charge is given by the formula $q = ne$,where $q$ is the total charge,$n$ is the number of electrons,and $e$ is the elementary charge $(e = 1.6 	imes 10^{-19} 	ext{ C})$.Given,$q = 3.52 	imes 10^{-7} 	ext{ C}$.To find the number of electrons transferred $(n)$,we rearrange the formula: $n = \frac{q}{e}$.Substituting the values: $n = \frac{3.52 	imes 10^{-7}}{1.6 	imes 10^{-19}}$.$n = 2.2 	imes 10^{12}$.Thus,the number of electrons transferred is $2.2 	imes 10^{12}$.

$A$ polythene piece rubbed with wool is found to have a negative charge of $3.52 \times 10^{-7} \text{ C}$. What is the number of electrons transferred?

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