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(D) The force acting on the particle due to the electric field is given by $F = qE$.Since the particle starts from rest and moves in the direction of

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$q E x$

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(D) The force acting on the particle due to the electric field is given by $F = qE$.Since the particle starts from rest and moves in the direction of the force,the work done by the electric field on the particle over a distance $x$ is $W = F \cdot x = (qE) \cdot x = qEx$.According to the work-energy theorem,the work done on a particle is equal to the change in its kinetic energy.Since the initial kinetic energy is $0$,the final kinetic energy is equal to the work done,which is $qEx$.

$A$ particle having mass $m$ and charge $q$ is at rest. On applying a uniform electric field $E$ on it,it starts moving. When this particle travels a distance $x$ in the direction of the force,its kinetic energy will be . . . . . . .

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