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(D) The self-inductance $L$ of a coil is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $\mu_0$ is the permeability of free space,$N$ is the n

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$L$

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(D) The self-inductance $L$ of a coil is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $\mu_0$ is the permeability of free space,$N$ is the number of turns,$A$ is the cross-sectional area,and $l$ is the length of the coil.From this formula,it is evident that the self-inductance $L$ depends only on the geometric parameters of the coil (number of turns,area,and length) and the core material.It is independent of the current $I$ flowing through the coil.Therefore,if the current changes from $I$ to $5I$,the self-inductance remains unchanged.Thus,the new self-inductance is $L$ $H$.

$A$ coil has $N$ turns and the current passing through it is $I$ ampere,resulting in a self-inductance of $L$ Henry. If the current changes to $5I$ $A$,the new self-inductance will be . . . . . . $H$.

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