A diffraction pattern is formed by blue light | vedclass

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(A) The correct answer is $A$. In a single-slit diffraction pattern, the angular width of the central maximum is given by $	heta = \frac{2\lambda}{a}

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the maxima and minima are broadened and become distant.

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(A) The correct answer is $A$. In a single-slit diffraction pattern, the angular width of the central maximum is given by $	heta = \frac{2\lambda}{a}$, where $\lambda$ is the wavelength of light and $a$ is the slit width. This shows that the diffraction effect is directly proportional to the wavelength $(	ext{diffraction} \propto \lambda)$. Since the wavelength of yellow light $(\lambda_{Y})$ is greater than the wavelength of blue light $(\lambda_{B})$, i.e., $\lambda_{Y} > \lambda_{B}$, the diffraction pattern produced by yellow light will be more spread out. Therefore, the maxima and minima are broadened and become more distant from each other.

$A$ diffraction pattern is formed by blue light. If the blue light is replaced by yellow light, then . . . . . . .

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