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(C) The reaction of formaldehyde $(HCHO)$ with a Grignard reagent $(RMgX)$ followed by acid hydrolysis yields a primary alcohol.In this case,the produ

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$CH_{3}MgI$

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(C) The reaction of formaldehyde $(HCHO)$ with a Grignard reagent $(RMgX)$ followed by acid hydrolysis yields a primary alcohol.In this case,the product is ethanol $(C_{2}H_{5}OH)$,which contains two carbon atoms.Since formaldehyde provides one carbon atom,the Grignard reagent must provide the other methyl group $(CH_{3})$.Therefore,the reagent $X$ is methylmagnesium iodide $(CH_{3}MgI)$.The reaction is: $HCHO + CH_{3}MgI$ $\rightarrow CH_{3}CH_{2}OMgI$ $\xrightarrow{H_{3}O^{+}} CH_{3}CH_{2}OH + Mg(OH)I$.

List-$I$ Reaction	List-$II$ Reagents
$A$. Hoffmann Degradation	$I$. Conc. $KOH, \Delta$
$B$. Clemmensen reduction	$II$. $CHCl_3, NaOH / H_3O^{+}$
$C$. Cannizzaro reaction	$III$. $Br_2, NaOH$
$D$. Reimer-Tiemann reaction	$IV$. $Zn-Hg / HCl$

$HCHO$ was treated with a reagent $X$. The product formed upon hydrolysis in the presence of an acid gave $C_{2}H_{5}OH$. The reagent $X$ is

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The structure of $(B)$ is

In the Cannizzaro reaction,the intermediate that will be the best hydride donor is:

Match List-$I$ with List-$II$.

List-$I$ Reaction List-$II$ Reagents

$A$. Hoffmann Degradation $I$. Conc. $KOH, \Delta$

$B$. Clemmensen reduction $II$. $CHCl_3, NaOH / H_3O^{+}$

$C$. Cannizzaro reaction $III$. $Br_2, NaOH$

$D$. Reimer-Tiemann reaction $IV$. $Zn-Hg / HCl$

What are the products formed in the following reaction?
$CH_3CH_2CHO + 2Cu^{2+} + 5OH^{-} \rightarrow X + Y + 3H_2O$

Which of the following fails to give the iodoform test?

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