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(D) The current in an $AC$ circuit containing a capacitor is given by $i = \frac{V}{\sqrt{R^2 + X_C^2}}$,where $X_C = \frac{1}{\omega C}$ is the capac

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a dielectric is introduced into the gap between the plates of the capacitor

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(D) The current in an $AC$ circuit containing a capacitor is given by $i = \frac{V}{\sqrt{R^2 + X_C^2}}$,where $X_C = \frac{1}{\omega C}$ is the capacitive reactance.When a dielectric is introduced into the gap between the plates of the capacitor,the capacitance $C$ increases $(C = K C_0)$.As $C$ increases,the capacitive reactance $X_C = \frac{1}{\omega C}$ decreases.Since the impedance $Z = \sqrt{R^2 + X_C^2}$ decreases,the current $i$ in the circuit increases.Consequently,the brightness of the bulb,which depends on the power dissipated $(P = i^2 R)$,increases.

$A$ capacitor and an inductance coil are connected in separate $AC$ circuits with a bulb glowing in both the circuits. The bulb glows more brightly when

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