A complex compound in which the oxidation num | vedclass

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(C) In $[Ni(CO)_4]$,the oxidation state of $Ni$ is calculated as: $x + 4(0) = 0 \Rightarrow x = 0$ (since $CO$ is a neutral ligand). For other options

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$[Ni(CO)_4]$

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(C) In $[Ni(CO)_4]$,the oxidation state of $Ni$ is calculated as: $x + 4(0) = 0 \Rightarrow x = 0$ (since $CO$ is a neutral ligand). For other options: $(a)$ $K_4[Fe(CN)_6]: 4(+1) + x + 6(-1) = 0 \Rightarrow x = +2$ $(b)$ $K_3[Fe(CN)_6]: 3(+1) + x + 6(-1) = 0 \Rightarrow x = +3$ $(d)$ $[Pt(NH_3)_4]Cl_2: x + 4(0) + 2(-1) = 0 \Rightarrow x = +2$

$A$ complex compound in which the oxidation number of a metal is zero is

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