A current of 2 ,A is passing through a metal | vedclass

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(D) The formula for the drift velocity $(v_{d})$ of electrons is given by: $v_{d} = \frac{I}{n e A}$ Where: $I = 2 \,A$ (Current) $n = 5 	imes 10^{26

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$\frac{1}{80} \,ms^{-1}$

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(D) The formula for the drift velocity $(v_{d})$ of electrons is given by: $v_{d} = \frac{I}{n e A}$ Where: $I = 2 \,A$ (Current) $n = 5 	imes 10^{26} \,m^{-3}$ (Number density of free electrons) $e = 1.6 	imes 10^{-19} \,C$ (Charge of an electron) $A = 2 	imes 10^{-6} \,m^{2}$ (Cross-sectional area) Substituting the values: $v_{d} = \frac{2}{(5 	imes 10^{26}) 	imes (1.6 	imes 10^{-19}) 	imes (2 	imes 10^{-6})}$ $v_{d} = \frac{2}{16 	imes 10^{26-19-6}} = \frac{2}{16 	imes 10^{1}} = \frac{2}{160} = \frac{1}{80} \,ms^{-1}$

$A$ current of $2 \,A$ is passing through a metal wire of cross-sectional area $2 \times 10^{-6} \,m^{2}$. If the number density of free electrons in the wire is $5 \times 10^{26} \,m^{-3}$, the drift speed of electrons is (Given, $e = 1.6 \times 10^{-19} \,C$)

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