ABC is a triangle,G is the centroid,and D is | vedclass

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(B) The centroid $G$ of a triangle $ABC$ divides the median $AD$ in the ratio $2:1$.Let $A = (2, 3)$,$G = (7, 5)$,and $D = (x, y)$.Using the section f

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$\left(\frac{19}{2}, 6\right)$

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(B) The centroid $G$ of a triangle $ABC$ divides the median $AD$ in the ratio $2:1$.Let $A = (2, 3)$,$G = (7, 5)$,and $D = (x, y)$.Using the section formula,the coordinates of $G$ are given by:$G = \left(\frac{2 \cdot x + 1 \cdot 2}{2+1}, \frac{2 \cdot y + 1 \cdot 3}{2+1}\right)$Equating the coordinates:$7 = \frac{2x + 2}{3}$ $\Rightarrow 21 = 2x + 2$ $\Rightarrow 2x = 19$ $\Rightarrow x = \frac{19}{2}$$5 = \frac{2y + 3}{3}$ $\Rightarrow 15 = 2y + 3$ $\Rightarrow 2y = 12$ $\Rightarrow y = 6$Therefore,the coordinates of point $D$ are $\left(\frac{19}{2}, 6\right)$.

$ABC$ is a triangle,$G$ is the centroid,and $D$ is the mid-point of $BC$. If $A = (2, 3)$ and $G = (7, 5)$,then the point $D$ is

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