(A) Mass of water $m = 6 \text{ tonnes} = 6000 \ kg$. Total height $h$ through which water is lifted = depth of well + height of first floor = $25 \ m

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(A) Mass of water $m = 6 \text{ tonnes} = 6000 \ kg$. Total height $h$ through which water is lifted = depth of well + height of first floor = $25 \ m + 35 \ m = 60 \ m$. Time taken $t = 20 \text{ minutes} = 20 \times 60 \ s = 1200 \ s$. Work done $W = mgh = 6000 \ kg \times 10 \ ms^{-2} \times 60 \ m = 3,600,000 \ J$. Power $P = \frac{W}{t} = \frac{3,600,000 \ J}{1200 \ s} = 3000 \ W$. Since $1 \ kW = 1000 \ W$,the power of the pump is $3 \ kW$.

Class 11 Physics Work, Energy, Power and Collision Power

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$A$ motor pump lifts $6$ tonnes of water from a well of depth $25 \ m$ to the first floor of height $35 \ m$ from the ground floor in $20$ minutes. The power of the pump (in $kW$) is: $[g=10 \ ms^{-2}]$

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$A$ motor pump lifts $6$ tonnes of water from a well of depth $25 \ m$ to the first floor of height $35 \ m$ from the ground floor in $20$ minutes. The power of the pump (in $kW$) is: $[g=10 \ ms^{-2}]$

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