$C_6H_5CH_2Cl$ $\xrightarrow{\text{Alc. } NH_3} A$ $\xrightarrow{2 CH_3Cl} B$. The product $B$ is

  • A
    $N, N$-dimethylphenylmethanamine
  • B
    $N, N$-dimethylbenzenamine
  • C
    $N$-benzyl-$N$-methylmethanamine
  • D
    phenyl-$N, N$-dimethylmethanamine

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