A crystalline solid XY_3 has a ccp arrangemen | vedclass

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(B) In a $ccp$ (cubic close-packed) arrangement,the number of octahedral voids is equal to the number of atoms,and the number of tetrahedral voids is

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$33\%$ of octahedral voids

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(B) In a $ccp$ (cubic close-packed) arrangement,the number of octahedral voids is equal to the number of atoms,and the number of tetrahedral voids is twice the number of atoms.Let the number of atoms of $Y$ be $N$.Then,the number of octahedral voids $= N$ and the number of tetrahedral voids $= 2N$.The formula of the compound is $XY_3$.This implies that for every $1$ atom of $X$,there are $3$ atoms of $Y$.If we have $N$ atoms of $Y$,then the number of atoms of $X$ is $N/3$.Since $X$ occupies octahedral voids,the fraction of octahedral voids occupied by $X$ is $\frac{N/3}{N} = 1/3$.Therefore,the percentage of octahedral voids occupied by $X$ is $\frac{1}{3} 	imes 100\% \approx 33\%$.

$A$ crystalline solid $XY_3$ has a $ccp$ arrangement for its element $Y$. $X$ occupies:

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