$H_{2}S$ is passed into $1 \ L$ of a solution containing $0.1 \ mole$ of $Zn^{2+}$ and $0.01 \ mole$ of $Cu^{2+}$ until the sulphide ion concentration reaches $8.1 \times 10^{-19} \ M$. Which one of the following statements is true? $[K_{sp}$ of $ZnS$ and $CuS$ are $3 \times 10^{-22}$ and $8 \times 10^{-36}$ respectively.$]$

  • A
    Only $ZnS$ precipitates
  • B
    Both $CuS$ and $ZnS$ precipitate
  • C
    Only $CuS$ precipitates
  • D
    No precipitation occurs

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What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes,there is no precipitation of iron sulphide? (For iron sulphide,$K_{sp} = 6.3 \times 10^{-18}$).

The sulphide ion concentration $[S^{2-}]$ in a saturated $H_2S$ solution is $1 \times 10^{-22} \ M$. Which of the following sulphides should be quantitatively precipitated by $H_2S$ in the presence of dilute $HCl$?
ProductSulphide Solubility $(K_{sp})$
$I$$1.74 \times 10^{-16}$
$II$$1.2 \times 10^{-22}$
$III$$8.2 \times 10^{-46}$
$IV$$5.0 \times 10^{-34}$

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If the solubility product constant $(K_{sp})$ of $Ni(OH)_2$ is $1.9 \times 10^{-15}$,the molar solubility of $Ni(OH)_2$ in $1.0 \ M \ NaOH$ is:

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