A toroid has 500 turns per metre length. If i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic field $B$ inside a toroid is given by $B = \mu_0 n I$, where $n$ is the number of turns per unit length and $I$ is the current.Given:

Vedclass · Accepted Answer

$0.628$

Vedclass · Answer

(B) The magnetic field $B$ inside a toroid is given by $B = \mu_0 n I$, where $n$ is the number of turns per unit length and $I$ is the current.Given: $n = 500 	ext{ m}^{-1}$, $I = 2 	ext{ A}$, $\mu_0 = 4\pi 	imes 10^{-7} 	ext{ T m/A}$.The magnetic energy density $u_B$ is given by $u_B = \frac{B^2}{2\mu_0}$.Substituting $B = \mu_0 n I$ into the formula, we get $u_B = \frac{(\mu_0 n I)^2}{2\mu_0} = \frac{\mu_0 n^2 I^2}{2}$.Calculating the value: $u_B = \frac{(4\pi 	imes 10^{-7}) 	imes (500)^2 	imes (2)^2}{2}$.$u_B = \frac{(4\pi 	imes 10^{-7}) 	imes 250000 	imes 4}{2} = 2\pi 	imes 10^{-7} 	imes 10^6 = 2\pi 	imes 10^{-1} = 0.2 	imes 3.14 = 0.628 	ext{ J/m}^3$.

$A$ toroid has $500$ turns per metre length. If it carries a current of $2 \text{ A}$, the magnetic energy density inside the toroid is: (in $\text{ J/m}^3$)

Similar Questions

$A$ $25\,cm$ long solenoid has radius $2\,cm$ and $500$ total number of turns. It carries a current of $15\,A.$ If it is equivalent to a magnet of the same size and magnetization $\vec M$ (magnetic moment per unit volume),then $\left| {\vec M} \right|$ is

$A$ solenoid $2 \,m$ long and $4 \,cm$ in diameter has $4$ layers of windings of $1000$ turns each and carries a current of $5 \,A$. What is the magnetic field at its centre along the axis? $\left[\mu_0=4 \pi \times 10^{-7} \,Wb / Am\right]$

The magnetic field intensity $(H)$ at the centre of a long solenoid carrying a current of $2 \ A$ is found to be $1000 \ A/m$. The number of turns per centimeter of the solenoid is: (Use $\mu_0 = 4 \pi \times 10^{-7} \ T \ m \ A^{-1}$)

$A$ long solenoid carrying a current produces a magnetic field $B$ along its axis. If the current is tripled and the number of turns per cm is halved, then the new value of the magnetic field will be:

What are electromagnets?

Vedclass Test Series

Exam Paper Generator

Online Exam Module