$A$ step-down transformer has $50$ turns on the secondary and $1000$ turns on the primary winding. If the transformer is connected to a $220 \ V, 1 \ A$ $A$.$C$. source,what is the output current of the transformer?

The number of turns in the primary and secondary coils of a transformer are $50$ and $200$ respectively. If the current in the primary coil is $4 \,A$, then the current in the secondary coil is: (in $\,A$)

Using the equation of power for an ideal transformer,prove $\frac{I_p}{I_s} = \frac{V_s}{V_p} = \frac{N_s}{N_p}$.

$A$ transformer has an efficiency of $80 \%$. The input power to the primary coil is $4 \text{ kW}$ at a voltage of $100 \text{ V}$. If the secondary voltage is $200 \text{ V}$,what are the primary and secondary currents,respectively?

In an ideal step-up transformer, the number of turns in the primary coil and secondary coil are $100$ and $200$ respectively. If the output current is found to be $5 \text{ A}$, then the input current will be . . . . . . . (in $\text{ A}$)

$A$ step-up transformer connected to a $220 \,V$ $AC$ line is to supply $22 \,kV$ for a neon sign in the secondary circuit. In the primary circuit,a fuse wire is connected which is to blow when the current in the secondary circuit exceeds $10 \,mA$. The turns ratio of the transformer is: