$A$ radioactive nucleus has specific binding energy $E_{1}$. It emits an $\alpha$-particle. The resulting nucleus has specific binding energy $E_{2}$. Then

  • A
    $E_{2}=0$
  • B
    $E_{2}=E_{1}$
  • C
    $E_{2} < E_{1}$
  • D
    $E_{2} > E_{1}$

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$M_p$ denotes the mass of a proton and $M_n$ that of a neutron. $A$ given nucleus,of binding energy $B$,contains $Z$ protons and $N$ neutrons. The mass $M(N, Z)$ of the nucleus is given by ($c$ is the velocity of light):

What is nuclear energy? Explain how nuclear energy is released from the curve of binding energy.

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Given below are two statements:
Statement $I$: For all elements, greater the mass of the nucleus, greater is the binding energy per nucleon.
Statement $II$: For all elements, nuclei with less binding energy per nucleon transform to nuclei with greater binding energy per nucleon.
In the light of the above statements, choose the correct answer from the options given below:

The curve of binding energy per nucleon as a function of atomic mass number has a sharp peak for the helium nucleus. This implies that helium

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