A bivalent metal has an equivalent mass of 32 | vedclass

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(D) The atomic mass of a metal is given by the formula: $	ext{Atomic mass} = 	ext{Equivalent mass} 	imes 	ext{Valency}$.Given,$	ext{Equivalent ma

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$188$

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(D) The atomic mass of a metal is given by the formula: $	ext{Atomic mass} = 	ext{Equivalent mass} 	imes 	ext{Valency}$.Given,$	ext{Equivalent mass} = 32$ and the metal is bivalent (valency $= 2$).Therefore,$	ext{Atomic mass} = 32 	imes 2 = 64$.The formula of the metal nitrate for a bivalent metal $M$ is $M(NO_3)_2$.The molecular mass of $M(NO_3)_2 = 	ext{Atomic mass of } M + 2 	imes (	ext{Atomic mass of } N + 3 	imes 	ext{Atomic mass of } O)$.Substituting the values: $64 + 2 	imes (14 + 3 	imes 16) = 64 + 2 	imes (14 + 48) = 64 + 2 	imes 62 = 64 + 124 = 188$.

$A$ bivalent metal has an equivalent mass of $32$. The molecular mass of the metal nitrate is

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