1 text{mole} of NaCl is doped with 10^{-5} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When $SrCl_{2}$ is added to $NaCl$,each $Sr^{2+}$ ion replaces two $Na^{+}$ ions to maintain electrical neutrality. One $Sr^{2+}$ ion creates one

Vedclass · Accepted Answer

$6.022 	imes 10^{18}$

Vedclass · Answer

(C) When $SrCl_{2}$ is added to $NaCl$,each $Sr^{2+}$ ion replaces two $Na^{+}$ ions to maintain electrical neutrality. One $Sr^{2+}$ ion creates one cationic vacancy. Therefore,$1 \ 	ext{mole}$ of $SrCl_{2}$ creates $1 \ 	ext{mole}$ of cationic vacancies. $10^{-5} \ 	ext{mole}$ of $SrCl_{2}$ will create $10^{-5} \ 	ext{mole}$ of cationic vacancies. Number of cationic vacancies $= 10^{-5} 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{18}$.

$1 \ \text{mole}$ of $NaCl$ is doped with $10^{-5} \ \text{mole}$ of $SrCl_{2}$. The number of cationic vacancies in the crystal lattice will be:

Similar Questions

Ionic solids with Schottky defect may contain in their structure

Which of the following is an incorrect statement?

What type of stoichiometric defect is shown by:
$(i)$ $ZnS$
$(ii)$ $AgBr$

Which one of the following crystals does not exhibit Frenkel defect?

Which of the following point defects are shown by $AgBr_{(s)}$ crystals?
$A$. Schottky defect
$B$. Frenkel defect
$C$. Metal excess defect
$D$. Metal deficiency defect

Vedclass Test Series

Exam Paper Generator

Online Exam Module