A crystalline solid X reacts with dil. HCl to | vedclass

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(D) The reactions involved are:$Na_2SO_3(s) + 2HCl(aq) \rightarrow 2NaCl(aq) + SO_2(g) + H_2O(l)$Here,$X = Na_2SO_3$ and $Y = SO_2$.$SO_2$ decolourise

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$Na_2SO_3, H_2S$

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(D) The reactions involved are:$Na_2SO_3(s) + 2HCl(aq) \rightarrow 2NaCl(aq) + SO_2(g) + H_2O(l)$Here,$X = Na_2SO_3$ and $Y = SO_2$.$SO_2$ decolourises acidified $KMnO_4$ solution:$2KMnO_4 + 5SO_2 + 2H_2O \rightarrow K_2SO_4 + 2MnSO_4 + 2H_2SO_4$When $H_2S$ (gas $Z$) is passed into an aqueous solution of $SO_2$ $(Y)$,colloidal sulphur is obtained:$SO_2(g) + 2H_2S(g) \rightarrow 3S(s) + 2H_2O(l)$Thus,$X = Na_2SO_3$ and $Z = H_2S$.

$A$ crystalline solid $X$ reacts with dil. $HCl$ to liberate a gas $Y$. $Y$ decolourises acidified $KMnO_4$. When a gas $Z$ is slowly passed into an aqueous solution of $Y$,colloidal sulphur is obtained. $X$ and $Z$ could be,respectively

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