A mature mRNA consists of 900 bases without a | vedclass

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(C) The genetic code is a triplet code,meaning $3$ nucleotides (bases) code for $1$ amino acid.Given that the $mRNA$ has $900$ bases and no stop codon

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$300$

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(C) The genetic code is a triplet code,meaning $3$ nucleotides (bases) code for $1$ amino acid.Given that the $mRNA$ has $900$ bases and no stop codon is present,the total number of codons is calculated by dividing the total number of bases by $3$.Number of codons = $\frac{900}{3} = 300$.Since each codon codes for one amino acid,the number of amino acids coded is $300$.

$A$ mature $mRNA$ consists of $900$ bases without any stop codon in between. Calculate the number of amino acids coded by this $mRNA$ during translation.

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