$A$ body of mass $10 \ mg$ is moving with a velocity of $100 \ ms^{-1}$. The wavelength of de-Broglie wave associated with it would be $(h=6.63 \times 10^{-34} \ Js)$.

  • A
    $6.63 \times 10^{-35} \ m$
  • B
    $6.63 \times 10^{-34} \ m$
  • C
    $6.63 \times 10^{-31} \ m$
  • D
    $6.63 \times 10^{-37} \ m$

Explore More

Similar Questions

If an electron is accelerated by a potential difference of $1.0 \times 10^4 \ V$,calculate its kinetic energy,frequency,and wavelength.

Difficult
View Solution

The de Broglie equation describes the relationship between the wavelength associated with the motion of an electron and its:

The velocities of two particles $A$ and $B$ are $0.05 \ ms^{-1}$ and $0.02 \ ms^{-1}$ respectively. The mass of $B$ is five times the mass of $A$. The ratio of their de-Broglie's wavelength is

The de Broglie wavelength of a car of mass $1000 \ kg$ and velocity $36 \ km/hr$ is

Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo