$A$ parallel beam of light of wavelength $6000 \text{ Å}$ is diffracted by a single slit of width $0.3 \text{ mm}$. The angular position of the first minima of the diffracted light is

In a double slit experiment,the two slits are $1\, mm$ apart and the screen is placed $1\, m$ away. $A$ monochromatic light of wavelength $500\, nm$ is used. What will be the width of each slit for obtaining ten maxima of the double slit pattern within the central maxima of the single slit pattern? .......$mm$

$A$ single slit of width $a$ is illuminated by a monochromatic light of wavelength $600 \, nm$. The value of $a$ for which the first minimum appears at $\theta = 30^{\circ}$ on the screen will be ........... $\mu m$.

Define diffraction.

Visible light of wavelength $6000 \times 10^{-8} \; cm$ falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at $60^{\circ}$ from the central maximum. If the first minimum is produced at $\theta_{1}$,then $\theta_{1}$ is close to.....$^{\circ}$

What happens if we close one slit in a Young's double-slit experiment?