$A$ coil of inductive reactance $ \frac{1}{\sqrt{3}} \Omega $ and resistance $ 1 \Omega $ is connected to a $ 200 \ V, 50 \ Hz $ $AC$ supply. The time lag between maximum voltage and current is

The given figure represents the phasor diagram of a series $LCR$ circuit connected to an $ac$ source. At the instant $t'$ when the source voltage is given by $V = V_0 \cos(\omega t')$,the current in the circuit will be:
Given: $V_{OL} = 3 \text{ V}$,$V_{OR} = \sqrt{3} \text{ V}$,$V_{OC} = 2 \text{ V}$.

An induction coil has an impedance of $10\,\Omega$. When an $AC$ signal of frequency $1000\,Hz$ is applied to the coil,the voltage leads the current by $45^o$. The inductance of the coil is

$A$ sinusoidal voltage of peak value $283 \, V$ and angular frequency $320 \, rad/s$ is applied to a series $LCR$ circuit. Given that $R = 5 \, \Omega$,$L = 25 \, mH$,and $C = 1000 \, \mu F$. The total impedance and the phase difference between the voltage across the source and the current will respectively be:

$A$ charged capacitor discharges through a resistance $R$ with time constant $\tau$. The two are now placed in series across an $AC$ source of angular frequency $\omega = \frac{1}{\tau}$. The impedance of the circuit will be-

In an $RC$ $AC$ circuit,the maximum voltage and maximum current are $100 \ V$ and $1.1 \ A$ respectively. If $X_{C} = 60 \ \Omega$ and $R = 80 \ \Omega$,then the power consumed in the circuit will be . . . . . . . (in $W$)