A particle of mass 500 text{ g} is at rest. I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The area under the $P-t$ graph is equal to the work done, which is equal to the change in kinetic energy $(\Delta K)$.Given mass $m = 500 	ext{ g

Vedclass · Accepted Answer

$5 	ext{ N-s}$

Vedclass · Answer

(C) The area under the $P-t$ graph is equal to the work done, which is equal to the change in kinetic energy $(\Delta K)$.Given mass $m = 500 	ext{ g} = 0.5 	ext{ kg}$.The area of the trapezoid $OABC$ is given by:$	ext{Area} = \frac{1}{2} 	imes (	ext{sum of parallel sides}) 	imes (	ext{height})$$	ext{Area} = \frac{1}{2} 	imes (2 + 8) 	imes 5 = \frac{1}{2} 	imes 10 	imes 5 = 25 	ext{ J}$.Since the particle starts from rest, the initial kinetic energy is $0$. Thus, the final kinetic energy at $t = 5 	ext{ s}$ is $K = 25 	ext{ J}$.We know that kinetic energy $K = \frac{p^2}{2m}$, where $p$ is the momentum.$25 = \frac{p^2}{2 	imes 0.5}$$25 = \frac{p^2}{1}$$p^2 = 25$$p = 5 	ext{ kg m/s} = 5 	ext{ N-s}$.

$A$ particle of mass $500 \text{ g}$ is at rest. It is free to move along a straight line. The power delivered to the particle varies with time according to the following graph. The momentum of the particle at $t = 5 \text{ s}$ is

Similar Questions

The figure shows the variation of a force $F$ acting on a particle along the $x$-axis. If the particle begins at rest at $x=0$,what is the particle's coordinate when it again has zero speed?

$A$ position-dependent force $F = 7 - 2x + 3x^2 \, N$ acts on a small body of mass $2 \, kg$ and displaces it from $x = 0$ to $x = 5 \, m$. The work done in joules is

An object starts from rest and is acted upon by a variable force $F$ as shown in the figure. If $-F_0$ is the initial value of the force at $x=0$,then the position of the object where it again comes to rest will be:

The figure shows the $F-x$ graph,where $F$ is the force applied and $x$ is the distance covered by the body along a straight-line path. Given that $F$ is in newton $(N)$ and $x$ is in metre $(m)$,calculate the total work done in joules $(J)$.

The graph of resistive force versus displacement for an object of mass $25 \ kg$ is given. If its velocity at $x = 0$ is $2 \ m/s$,then its kinetic energy at $x = 4 \ m$ is ..... $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module