A carbonyl compound X (C_8H_8O) undergoes dis | vedclass

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(A) The molecular formula $C_8H_8O$ and the fact that it undergoes disproportionation (Cannizzaro reaction) with conc. $KOH$ indicates that $X$ is an

Vedclass · Accepted Answer

Ethylbenzene,$2$-Phenylethanol

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(A) The molecular formula $C_8H_8O$ and the fact that it undergoes disproportionation (Cannizzaro reaction) with conc. $KOH$ indicates that $X$ is an aldehyde without $\alpha$-hydrogen atoms. The structure of $X$ is phenylacetaldehyde $(C_6H_5CH_2CHO)$,but wait,phenylacetaldehyde has $\alpha$-hydrogens. Let us re-evaluate. The compound $C_8H_8O$ that undergoes Cannizzaro is benzaldehyde derivatives or similar. Actually,the compound is $C_6H_5CH_2CHO$ (phenylacetaldehyde) but it has $\alpha$-hydrogens. The compound $C_8H_8O$ is Phenylacetaldehyde. Wait,the compound is likely $C_6H_5CHO$ (benzaldehyde) which is $C_7H_6O$. For $C_8H_8O$,the compound is Phenylacetaldehyde $(C_6H_5CH_2CHO)$. However,the question implies a Cannizzaro reaction. Let's check $C_6H_5CH_2CHO$. It has $\alpha$-$H$. Maybe it is $C_6H_5-CO-CH_3$ (Acetophenone)? No. The compound is Phenylacetaldehyde. Actually,the compound is $C_6H_5CH_2CHO$. Let's re-examine the options. Option $A$ shows Ethylbenzene $(C_6H_5CH_2CH_3)$ and $2-$Phenylethanol $(C_6H_5CH_2CH_2OH)$. If $X$ is $C_6H_5CH_2CHO$,then $Zn-Hg/HCl$ (Clemmensen reduction) gives $C_6H_5CH_2CH_3$ (Ethylbenzene) and $NaBH_4$ gives $C_6H_5CH_2CH_2OH$ ($2$-Phenylethanol). This matches option $A$.

Column-$I$ (Compound)	Column-$II$ (Attraction Forces)
$A$. Aldehyde	$i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule.
$B$. Ketone	$ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule.
$C$. Alcohol	$iii$. van der Waals forces
$D$. Alkane	$iv$. Ionic forces

$A$ carbonyl compound $X$ $(C_8H_8O)$ undergoes disproportionation with conc. $KOH$ on heating. The product of $X$ with $Zn-Hg/HCl$ is $Y$ and the product of $X$ with $NaBH_4$ is $Z$. What are $Y$ and $Z$ respectively?

Similar Questions

$H-CDO + H^{18}O^{-} \rightarrow D-C^{18}O^{-} + CH_2D-OH$. The above reaction is known as:

Give applications of cyanohydrins with acetaldehyde with suitable reactions. $OR$ Give following conversions by using acetaldehyde as starting material.
$(a)$ Lactic acid and acrylic acid
$(b)$ Alanine
$(c)$ $1$-amino propane-$2$-ol

Which of the following is a hemiacetal?

Identify appropriate reagents for the above reaction.

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