$A$ bulb of resistance $280 \Omega$ is supplied with a $200 V$ $AC$ supply. What is the peak current?

$A$ resistance of $20 \Omega$ is connected to a source of an alternating potential $V = 200 \sin (10 \pi t)$. If $t$ is the time taken by the current to change from the peak value to rms value,then $t$ is (in seconds).

An $AC$ source rated $220\, V, 50\, Hz$ is connected to a resistor. The time taken by the current to change from its maximum value to the $rms$ value is:

The peak value of an alternating current is $5 \ A$ and its frequency is $60 \ Hz$. Find its $rms$ value and the time taken to reach the peak value of current starting from zero.

The $AC$ voltage across a resistance can be measured using a

In an $AC$ generator, induced emf $\varepsilon = 0$ at $t = 0$, then its value . . . . . .