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Question

(A) $1$. Calculate the millimoles of $H_2SO_4$ taken: $50 \ mL 	imes 0.5 \ M = 25 \ mmol$. $2$. Calculate the millimoles of $NaOH$ used to neutralize

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(A) $1$. Calculate the millimoles of $H_2SO_4$ taken: $50 \ mL 	imes 0.5 \ M = 25 \ mmol$. $2$. Calculate the millimoles of $NaOH$ used to neutralize the excess $H_2SO_4$: $60 \ mL 	imes 0.5 \ M = 30 \ mmol$. $3$. Since $2 \ mol$ of $NaOH$ neutralize $1 \ mol$ of $H_2SO_4$,the $H_2SO_4$ neutralized by $NaOH$ is $30 / 2 = 15 \ mmol$. $4$. Millimoles of $H_2SO_4$ reacted with ammonia = $25 - 15 = 10 \ mmol$. $5$. Since $1 \ mol$ of $H_2SO_4$ reacts with $2 \ mol$ of $NH_3$,the millimoles of $NH_3$ (and thus $N$) = $10 	imes 2 = 20 \ mmol$. $6$. Mass of nitrogen = $20 \ mmol 	imes 14 \ g/mol = 280 \ mg$. $7$. Percentage of nitrogen = $(	ext{Mass of } N / x) 	imes 100 = 56$. $8$. $(280 / x) 	imes 100 = 56 \implies x = 28000 / 56 = 500 \ mg$.

Column-$I$	Column-$II$
$(i).$ Magnesium pyrophosphate	$(a).$ $I_2O_5$
$(ii).$ Barium sulphate	$(b).$ $AgX$
$(iii).$ Iodide pentoxide	$(c).$ $Mg_2P_2O_7$
$(iv).$ Silver halide	$(d).$ $BaSO_4$

Similar Questions

Match Column-$I$ and Column-$II$ with the correct relation:

Column-$I$ Column-$II$

$(i).$ Magnesium pyrophosphate $(a).$ $I_2O_5$

$(ii).$ Barium sulphate $(b).$ $AgX$

$(iii).$ Iodide pentoxide $(c).$ $Mg_2P_2O_7$

$(iv).$ Silver halide $(d).$ $BaSO_4$

What is the reason for passing dry air through the combustion tube during the estimation of $C$ and $H$?

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Explain the Carius method and its principle for the estimation of phosphorus in an organic compound.

An organic compound gives $0.220 \ g$ of $CO_2$ and $0.126 \ g$ of $H_2O$ on complete combustion. If the $\%$ of carbon is $24$,then the $\%$ of hydrogen is $...... \times 10^{-1}$. $(Nearest \ integer)$

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