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(B) The linear momentum remains conserved before and after the collision. Let $m_1 = 2 \ kg$,$u_1 = 36 \ km/h = 10 \ m/s$,$m_2 = 3 \ kg$,and $u_2 = 0

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(B) The linear momentum remains conserved before and after the collision. Let $m_1 = 2 \ kg$,$u_1 = 36 \ km/h = 10 \ m/s$,$m_2 = 3 \ kg$,and $u_2 = 0 \ m/s$.Using the conservation of linear momentum: $m_1 u_1 + m_2 u_2 = (m_1 + m_2) v$$2 \ kg 	imes 10 \ m/s + 3 \ kg 	imes 0 = (2 \ kg + 3 \ kg) v$$20 = 5v \Rightarrow v = 4 \ m/s$.The initial kinetic energy is $K E_i = \frac{1}{2} m_1 u_1^2 = \frac{1}{2} 	imes 2 	imes (10)^2 = 100 \ J$.The final kinetic energy is $K E_f = \frac{1}{2} (m_1 + m_2) v^2 = \frac{1}{2} 	imes 5 	imes (4)^2 = \frac{1}{2} 	imes 5 	imes 16 = 40 \ J$.The loss in kinetic energy is $\Delta K E = K E_i - K E_f = 100 \ J - 40 \ J = 60 \ J$.

$A$ metal ball of mass $2 \ kg$ moving with a velocity of $36 \ km/h$ has a head-on collision with a stationary ball of mass $3 \ kg$. After the collision,if both balls move together,the loss in kinetic energy due to the collision is: (in $J$)

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