$A$ $8 \Omega$ resistor is connected to a battery that has an internal resistance of $0.2 \Omega$. If the voltage across the battery (the terminal voltage) is $10 \ V$,then the emf of the battery is (in $V$)

Find the potential difference between points $A$ and $B$ in the following circuit. (in $V$)

In the circuit shown in the figure,the resistance of the voltmeter is $6 \, k\Omega$. The voltmeter reading will be ................. $V$.

$A$ $5\, V$ battery with internal resistance $2\, \Omega$ and a $2\, V$ battery with internal resistance $1\, \Omega$ are connected to a $10\, \Omega$ resistor as shown in the figure. The current in the $10\, \Omega$ resistor is:

$A$ current of $6 \ A$ enters one corner $P$ of an equilateral triangle $PQR$ having three wires of resistance $2 \ \Omega$ each and leaves by the corner $R$ as shown in the figure. Then the currents $I_1$ and $I_2$ are respectively:

Four resistances $40 \ \Omega, 60 \ \Omega, 90 \ \Omega$,and $110 \ \Omega$ form the arms of a quadrilateral $ABCD$. $A$ battery of emf $40 \ V$ with negligible internal resistance is connected across $AC$. Find the potential difference across $BD$. (in $V$)