A purple colored compound of Manganese (X) de | vedclass

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(C) The purple colored compound $(X)$ is $KMnO_4$. Upon heating,$KMnO_4$ decomposes to liberate oxygen and forms $K_2MnO_4$ $(Y)$ and $MnO_2$ $(Z)$. T

Vedclass · Accepted Answer

$X = KMnO_4, Y = K_2MnO_4, Z = MnO_2$

Vedclass · Answer

(C) The purple colored compound $(X)$ is $KMnO_4$. Upon heating,$KMnO_4$ decomposes to liberate oxygen and forms $K_2MnO_4$ $(Y)$ and $MnO_2$ $(Z)$. The reaction is: $2KMnO_4(X) \xrightarrow{\Delta} K_2MnO_4(Y) + MnO_2(Z) + O_2$. Compound $MnO_2$ $(Z)$ reacts with $KOH$ in the presence of an oxidizing agent like potassium nitrate $(KNO_3)$ to form potassium manganate $(K_2MnO_4)$ $(Y)$. The reaction is: $2MnO_2(Z) + 4KOH + O_2 \rightarrow 2K_2MnO_4(Y) + 2H_2O$. Thus,the compounds are $X = KMnO_4, Y = K_2MnO_4, Z = MnO_2$.

$A$ purple colored compound of Manganese $(X)$ decomposes on heating to liberate oxygen and forms compounds of Manganese $(Y)$ and $(Z)$. Compound $(Z)$ reacts with $KOH$ in the presence of potassium nitrate to give compound $(Y)$. Compounds $(X)$,$(Y)$,and $(Z)$ respectively are:

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