$A$ lamp delivers a luminous flux of $100 \,W$ to an absorber of area $1 \,cm^2$. The force due to radiation pressure is

  • A
    $3.3 \times 10^{-4} \,N$
  • B
    $16.5 \times 10^{-7} \,N$
  • C
    $3.3 \times 10^{-6} \,N$
  • D
    $3.3 \times 10^{-7} \,N$

Explore More

Similar Questions

What is the force exerted on a mirror of area $40 \, cm^2$ when an $EM$ wave of intensity $6 \, W/m^2$ is incident on it?

$A$ bulb of power $660 \,W$ radiates uniformly in all directions. The pressure exerted by the radiation on the surface at a distance of $5 \,m$ is

$A$ small object at rest absorbs a light pulse of power $20\,mW$ and duration $300\,ns$. Assuming the speed of light as $3 \times 10^8\,m/s$,the momentum of the object becomes equal to $.........\times 10^{-17}\,kg\,m/s$.

Light is incident normally on a completely absorbing surface with an energy flux of $25\,W\,cm^{-2}.$ If the surface has an area of $25\,cm^2,$ the maximum momentum transferred to the surface in $40\,min$ time duration will be

If the radiant energy received from an electric bulb per second is $25 \ J/s$ and the velocity of electromagnetic waves is $c = 3 \times 10^8 \ m/s$,then the force exerted on the surface in one second is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo