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(C) The magnetic flux $\phi$ through a single loop is given by $\phi = B \cdot A \cdot \cos(	heta)$.Since the plane of the coil is normal to the magn

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$0.7$

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(C) The magnetic flux $\phi$ through a single loop is given by $\phi = B \cdot A \cdot \cos(	heta)$.Since the plane of the coil is normal to the magnetic field,the angle $	heta$ between the area vector and the magnetic field is $0^\circ$,so $\cos(0^\circ) = 1$.Thus,$\phi = B \cdot A$.The induced emf $\epsilon$ in a coil with $N$ turns is given by Faraday's Law: $\epsilon = -N \frac{d\phi}{dt}$.Here,$N = 100$,the area $A = (10 \ cm)^2 = (0.1 \ m)^2 = 0.01 \ m^2$,and the rate of change of magnetic field $\frac{dB}{dt} = 0.7 \ T \ s^{-1}$.Substituting these values: $\epsilon = N \cdot A \cdot \frac{dB}{dt} = 100 	imes 0.01 	imes 0.7$.$\epsilon = 1 	imes 0.7 = 0.7 \ V$.

$A$ coil having $100$ square loops each of side $10 \ cm$ is placed such that its plane is normal to a magnetic field,which is changing at a rate of $0.7 \ T \ s^{-1}$. The emf induced in the coil is (in $V$)

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