X_2 is used in the refining of Ti metal by th | vedclass

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Question

(C) The van Arkel method for the refining of $Ti$ metal involves the formation of a volatile iodide,$TiI_4$,which is subsequently decomposed to yield

Vedclass · Accepted Answer

$I_2, I_2$

Vedclass · Answer

(C) The van Arkel method for the refining of $Ti$ metal involves the formation of a volatile iodide,$TiI_4$,which is subsequently decomposed to yield pure metal. Thus,$X_2$ is $I_2$.$Y_2$ does not liberate $O_2$ from water and does not form $HY$ and $HOY$ with water. $I_2$ is the only halogen that does not react with water to produce $O_2$ or form $HX$ and $HOX$ species under standard conditions. Therefore,$Y_2$ is also $I_2$.The reactions are:$(i)$ $	ext{Impure } Ti + 2I_2$ $ightarrow TiI_4$ $\xrightarrow{\Delta} Ti + 2I_2$(ii) $I_2 + H_2O ightarrow 	ext{No reaction to form } O_2, HI, 	ext{ or } HOI$.Thus,both $X_2$ and $Y_2$ are $I_2$. The correct option is $(C)$.

$X_2$ is used in the refining of $Ti$ metal by the van Arkel method. $Y_2$ does not liberate $O_2$ from water and does not form $HY$ and $HOY$ with water. $X_2$ and $Y_2$ are respectively:

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