Z is an aromatic compound with substituents P | vedclass

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(D) The starting material is $2-$methylhexane. Upon reaction with $Cr_2O_3$ at $773 \ K$ and $10-20 \ atm$,it undergoes cyclization and aromatization

Vedclass · Accepted Answer

$-COOH, -NO_2$

Vedclass · Answer

(D) The starting material is $2-$methylhexane. Upon reaction with $Cr_2O_3$ at $773 \ K$ and $10-20 \ atm$,it undergoes cyclization and aromatization to form toluene (compound $X$). Reaction of toluene with $KMnO_4$ in alkaline medium followed by acidification $(H_3O^+)$ oxidizes the methyl group to a carboxylic acid group,forming benzoic acid (compound $Y$). Nitration of benzoic acid using concentrated $HNO_3$ and $H_2SO_4$ at $Comparing the structure of $Z$ with the given substituents,$P$ is $-COOH$ and $Q$ is $-NO_2$.

$Z$ is an aromatic compound with substituents $P$ and $Q$. What are $P$ and $Q$?

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