$A$ bullet of mass $20 \,g$ moving with $500 \,ms^{-1}$ is pierced $1 \,cm$ into a wooden block. The retarding force experienced by the bullet is:

$A$ particle of mass $m$ is moving in a straight line with momentum $p$. Starting at time $t = 0$,a force $F = kt$ acts in the same direction on the moving particle during time interval $T$ so that its momentum changes from $p$ to $3p$. Here $k$ is a constant. The value of $T$ is

The linear momentum $p$ of a body of mass $5 \,kg$ varies with time $t$ as $p = 5t^2 + t + 5$. It follows that the body is moving with:

$A$ body of mass $0.05 \ kg$ is observed to fall with an acceleration of $9.5 \ ms^{-2}$. The opposing force of air on the body is $(g = 9.8 \ ms^{-2})$.

$A$ player caught a cricket ball of mass $150 \ g$ moving at a rate of $20 \ m/s$. If the catching process is completed in $0.1 \ s$,the force of the blow exerted by the ball on the hand of the player is equal to .......... $N$.

The force required to stop a body of mass $10 \,kg$ moving along a straight line path with a velocity of $10 \,ms^{-1}$ in a time of $10 \,s$ is (in $\,N$)