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(C) According to the Ampere-Maxwell law,the magnetic field $B$ at a distance $r$ from the axis between the plates of a charging capacitor is given by

Vedclass · Accepted Answer

$\frac{\mu_0 I_D}{2 \pi r}$

Vedclass · Answer

(C) According to the Ampere-Maxwell law,the magnetic field $B$ at a distance $r$ from the axis between the plates of a charging capacitor is given by the line integral of the magnetic field around a circular loop of radius $r$.For $r > R$,the displacement current enclosed by the loop is equal to the total displacement current $I_D$ passing through the capacitor.Applying Ampere-Maxwell law: $\oint B \cdot dl = \mu_0 I_{enclosed}$.Since the current is $I_D$,we have $B(2 \pi r) = \mu_0 I_D$.Therefore,the magnetic field is $B = \frac{\mu_0 I_D}{2 \pi r}$.

$A$ circular parallel plate capacitor of radius $R$ and spacing $d$ is being charged by a constant current $I_D$. Find the magnetic field between the plates at a distance $r$ from the axis,where $r > R$.

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