A charge 'q' is spread uniformly over an isol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The equivalent current '$I$' produced by the rotating ring is given by the charge per unit time: $I = \frac{q}{T} = \frac{q \omega}{2 \pi}$ where

Vedclass · Accepted Answer

$\frac{q \omega R^2}{2}$

Vedclass · Answer

(C) The equivalent current '$I$' produced by the rotating ring is given by the charge per unit time: $I = \frac{q}{T} = \frac{q \omega}{2 \pi}$ where '$T = \frac{2 \pi}{\omega}$' is the time period of rotation. The magnetic dipole moment '$M$' of a current loop is given by the product of current '$I$' and the area '$A$' of the loop: $M = I 	imes A$ Since the area of the ring is '$A = \pi R^2$',we have: $M = \left( \frac{q \omega}{2 \pi} ight) 	imes (\pi R^2)$ $M = \frac{q \omega R^2}{2}$

$A$ charge '$q$' is spread uniformly over an isolated ring of radius '$R$'. The ring is rotated about its natural axis with angular speed $\omega$. The magnetic dipole moment of the ring is

Similar Questions

If the difference between the roots of the equations ${x^2} + ax + b = 0$ and ${x^2} + bx + a = 0$ is the same,and $a \ne b$,then:

The number of triangles that can be formed by choosing the vertices from a set of $12$ points,seven of which lie on the same straight line,is

$A$ patient brought to a hospital with myocardial infarction is normally immediately given

If the distance between the points $(a \cos \theta, a \sin \theta)$ and $(a \cos \phi, a \sin \phi)$ is $2a$,then $\theta$ is equal to

Assertion: One molal aqueous solution of glucose contains $180 \ g$ of glucose in $1 \ kg$ of water.
Reason: $A$ solution containing one mole of solute in $1000 \ g$ of solvent is called a one molal solution.

Vedclass Test Series

Exam Paper Generator

Online Exam Module