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(B) According to Curie's law, the magnetization $M$ of a paramagnetic material is given by $M = C \frac{B}{T}$, where $B$ is the external magnetic fie

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$0.2$

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(B) According to Curie's law, the magnetization $M$ of a paramagnetic material is given by $M = C \frac{B}{T}$, where $B$ is the external magnetic field, $T$ is the absolute temperature, and $C$ is Curie's constant.Given $M_1 = 0.8 	ext{ A m}^{-1}$, $B_1 = 0.8 	ext{ T}$, and $T_1 = 5 	ext{ K}$.Substituting these values into the formula: $0.8 = C \frac{0.8}{5} \Rightarrow C = 5 	ext{ K}$.Now, for the new temperature $T_2 = 20 	ext{ K}$ with the same magnetic field $B_2 = 0.8 	ext{ T}$, the new magnetization $M_2$ is:$M_2 = C \frac{B_2}{T_2} = 5 	imes \frac{0.8}{20} = \frac{4}{20} = 0.2 	ext{ A m}^{-1}$.

$A$ paramagnetic sample shows a net magnetization of $0.8 \text{ A m}^{-1}$ when placed in an external magnetic field of strength $0.8 \text{ T}$ at a temperature of $5 \text{ K}$. If the temperature is raised to $20 \text{ K}$, then the magnetization becomes: (in $\text{ A m}^{-1}$)

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