A uniform wire of length 10 m and diameter 0 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Length of the wire,$L = 10 \ m$,diameter,$D = 0.6 	imes 10^{-3} \ m$,Poisson's ratio,$\sigma = 0.3$,and change in wire length,$\Delta L =

Vedclass · Accepted Answer

$10.8 	imes 10^{-8} \ m$

Vedclass · Answer

(C) Given: Length of the wire,$L = 10 \ m$,diameter,$D = 0.6 	imes 10^{-3} \ m$,Poisson's ratio,$\sigma = 0.3$,and change in wire length,$\Delta L = 6 	imes 10^{-3} \ m$.The Poisson's ratio is defined as the ratio of lateral strain to longitudinal strain:$\sigma = \frac{	ext{lateral strain}}{	ext{longitudinal strain}} = \frac{\Delta D / D}{\Delta L / L}$Rearranging the formula to solve for the change in diameter $\Delta D$:$\Delta D = \sigma 	imes D 	imes \frac{\Delta L}{L}$Substituting the given values:$\Delta D = 0.3 	imes (0.6 	imes 10^{-3} \ m) 	imes \frac{6 	imes 10^{-3} \ m}{10 \ m}$$\Delta D = 0.3 	imes 0.6 	imes 10^{-3} 	imes 6 	imes 10^{-4} \ m$$\Delta D = 1.08 	imes 10^{-7} \ m = 10.8 	imes 10^{-8} \ m$Therefore,the change in the diameter of the wire is $10.8 	imes 10^{-8} \ m$. The correct option is $C$.

$A$ uniform wire of length $10 \ m$ and diameter $0.6 \ mm$ is stretched by $6 \ mm$ with a certain force. If the Poisson's ratio of the material of the wire is $0.3$,then the change in diameter of the wire is

Similar Questions

If the longitudinal strain of a stretched wire is $0.2 \%$ and the Poisson's ratio of the material of the wire is $0.3$,then the volume strain of the wire is (in $\%$)

When a wire of length $10 \ m$ is subjected to a force of $100 \ N$ along its length, the lateral strain produced is $0.01 \times 10^{-3} \ m$. The Poisson's ratio was found to be $0.4$. If the area of cross-section of the wire is $0.025 \ m^2$, its Young's modulus is:

There is no change in the volume of a wire due to a change in its length on stretching. The Poisson's ratio of the material of the wire is:

The Poisson's ratio cannot have the value:

$A$ tension of $20 \,N$ is applied to a copper wire of cross-sectional area $0.01 \,cm^2$. The Young's modulus of copper is $1.1 \times 10^{11} \,N/m^2$ and the Poisson's ratio is $0.32$. The decrease in the cross-sectional area of the wire is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module