BF_3 reacts with NaH at 450 K to form NaF an | vedclass

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(C) The reaction of $BF_3$ with $NaH$ at $450 \ K$ produces diborane $(B_2 H_6)$ as $X$: $2 BF_3 + 6 NaH \xrightarrow{450 \ K} 6 NaF + B_2 H_6 (X)$ Wh

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$LiBH_4$

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(C) The reaction of $BF_3$ with $NaH$ at $450 \ K$ produces diborane $(B_2 H_6)$ as $X$: $2 BF_3 + 6 NaH \xrightarrow{450 \ K} 6 NaF + B_2 H_6 (X)$ When diborane $(X)$ reacts with $LiH$ in the presence of diethyl ether,it forms lithium borohydride $(LiBH_4)$ as $Y$: $B_2 H_6 + 2 LiH \xrightarrow{	ext{Diethyl ether}} 2 LiBH_4 (Y)$ Therefore,$Y$ is $LiBH_4$.

$BF_3$ reacts with $NaH$ at $450 \ K$ to form $NaF$ and $X$. When $X$ reacts with $LiH$ in diethyl ether,$Y$ is formed. What is $Y$?

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