X_2 reacts with water to form HX_{(aq)} and H | vedclass

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(B) $1$. For $X_2$: $Cl_2$ and $Br_2$ react with water to form $HX$ and $HOX$ (disproportionation reaction). $Cl_2 + H_2O \rightarrow HCl + HOCl$.$2$.

Vedclass · Accepted Answer

$Cl_2, F_2, I_2$

Vedclass · Answer

(B) $1$. For $X_2$: $Cl_2$ and $Br_2$ react with water to form $HX$ and $HOX$ (disproportionation reaction). $Cl_2 + H_2O \rightarrow HCl + HOCl$.$2$. For $Y_2$: $F_2$ is a very strong oxidizing agent and reacts with water to oxidize it to $O_2$. $2F_2 + 2H_2O \rightarrow 4H^+ + 4F^- + O_2$.$3$. For $Z_2$: $I_2$ is the least reactive and does not react with water spontaneously. Thus,$X_2 = Cl_2$,$Y_2 = F_2$,and $Z_2 = I_2$.

$X_2$ reacts with water to form $HX_{(aq)}$ and $HOX_{(aq)}$. $Y_2$ reacts with water to form $O_{2(g)}$,$Y^{-}_{(aq)}$ and $H^{+}_{(aq)}$. $Z_2$ does not react with water. $X_2, Y_2, Z_2$ are respectively

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